Khan Academy Teste 2 Google Sala de Aula Qual é o resultado da divisão do monômio ((27y^(12))/(3y^(7))) ? Escolha 1 resposta: (A) 9y^(7) (B) 9y^(5)

<p>To find the result of the division of the monomial \((27y^{12}/3y^7)\), we can follow these steps:<br /><br />1. Divide the numerical coefficients: \(27/3 = 9\).<br />2. Use the rule for dividing like bases, where we subtract the exponent in the denominator from the exponent in the numerator: \(y^{12} / y^7 = y^{(12-7)} = y^5\).<br /><br />Therefore, the answer is \(9y^5\), option B.</p>