Pergunta

Factor each "SIMPLE")TRIN 11) x^2+11x+28
Solução

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HermíniaProfissional · Tutor por 6 anos
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<br /><br />To factor the quadratic expression $x^{2}+11x+28$, we need to find two numbers that multiply to 28 (the constant term) and add up to 11 (the coefficient of the linear term).<br /><br />The two numbers that satisfy these conditions are 4 and 7, since $4 \times 7 = 28$ and $4 + 7 = 11$.<br /><br />Therefore, we can factor the expression as follows:<br /><br />\[x^{2}+11x+28 = (x+4)(x+7)\]<br /><br />So, the factored form of the expression $x^{2}+11x+28$ is \[(x+4)(x+7)\].
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