Pergunta

1. Resolva as expressões abaixo: a) 2,31+4,08+3,2= b) 4,03+200+51,2= m) (2,32times 4,90)/(0,4)= C) 32,4-21,3= n) (0,02times 4,32)/(8)= d) 33,45-48= 0) (1)/(2)+(1)/(3)= e) 4,23-10,56= Đ 5,52-6,30+1,25= p) (2)/(3)+(1)/(4)= g) 13,1-5,23-6,13= h) 2,1times 3,2= i) 48,2times 0,031= q) (5)/(9)-(1)/(3)= j) 3,21times 2,003= r) (2)/(3)-(1)/(4)= k) 8,48/0,02= 1) 62,5/0,25=
Solução

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ÚrsulaEspecialista · Tutor por 3 anos
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a) $2,31+4,08+3,2=9,59$<br />b) $4,03+200+51,2=255,23$<br />m) $\frac {2,32\times 4,90}{0,4}=28,68$<br />C) $32,4-21,3=11,1$<br />n) $\frac {0,02\times 4,32}{8}=0,0108$<br />d) $33,45-48=-14,55$<br />0) $\frac {1}{2}+\frac {1}{3}=0,83$<br />e) $4,23-10,56=-6,33$<br />Đ) $5,52-6,30+1,25=0,47$<br />p) $\frac {2}{3}+\frac {1}{4}=0,95$<br />g) $13,1-5,23-6,13=1,74$<br />h) $2,1\times 3,2=6,72$<br />1) $48,2\times 0,031=1,4972$<br />q) $\frac {5}{9}-\frac {1}{3}=0,2222$<br />j) $3,21\times 2,003=6,42603$<br />r) $\frac {2}{3}-\frac {1}{4}=0,4167$<br />k) $8,48/0,02=424$<br />1) $62,5/0,25=250$
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