-x^2+5x+3=0 a=underline ( ); b=underline ( ); c=underline ( )

To solve the quadratic equation \(-x^2 + 5x + 3 = 0\), we need to identify the coefficients \(a\), \(b\), and \(c\) in the standard form of a quadratic equation \(ax^2 + bx + c = 0\).<br /><br />Given equation: \(-x^2 + 5x + 3 = 0\)<br /><br />We can rewrite it in the standard form as:<br />\[ -1 \cdot x^2 + 5 \cdot x + 3 = 0 \]<br /><br />From this, we can identify the coefficients:<br />\[ a = -1 \]<br />\[ b = 5 \]<br />\[ c = 3 \]<br /><br />So, the values are:<br />\[ a = -1 \]<br />\[ b = 5 \]<br />\[ c = 3 \]