11) Calcule os arranjos e combinações: a) A_(4,3)= b) A_(5,1)= C) A_(8,4)= Arranjoarrow A_(n,p)=(n!)/((n-p)!) d) C_(5,5)= e) C_(6,3)= Combinactilde (a)oarrow C_(n,p)=(n!)/(p!(n-p)!)

a) $A_{4,3}=\frac{4!}{(4-3)!}=\frac{4!}{1!}=\frac{24}{1}=24$<br />b) $A_{5,1}=\frac{5!}{(5-1)!}=\frac{5!}{4!}=\frac{120}{24}=5$<br />c) $A_{8,4}=\frac{8!}{(8-4)!}=\frac{8!}{4!}=\frac{40320}{24}=1680$<br />d) $C_{5,5}=\frac{5!}{5!(5-5)!}=\frac{5!}{5!0!}=\frac{120}{120 \cdot 1}=1$<br />e) $C_{6,3}=\frac{6!}{3!(6-3)!}=\frac{6!}{3!3!}=\frac{720}{6 \cdot 6}=20$<br /><br />Portanto, as respostas corretas são:<br />a) $A_{4,3}=24$<br />b) $A_{5,1}=5$<br />c) $A_{8,4}=1680$<br />d) $C_{5,5}=1$<br />e) $C_{6,3}=20$