30. Solve 3(x-4)^2-12=0 x=-2or-6 x=2or6 x=10 x=89

To solve the equation $3(x-4)^{2}-12=0$, we can follow these steps:<br /><br />1. Add 12 to both sides of the equation:<br />$3(x-4)^{2} = 12$<br /><br />2. Divide both sides by 3:<br />$(x-4)^{2} = 4$<br /><br />3. Take the square root of both sides:<br />$x-4 = \pm 2$<br /><br />4. Solve for x:<br />$x = 4 \pm 2$<br /><br />Therefore, the solutions to the equation are $x = 6$ and $x = 2$.<br /><br />So correct answer is $x=2or6$.