Given the following formula.solve for h. S=2(pi r^2+pi rh) A h=(S)/(2pi r^2) B h=(S)/(2pi r)-r C. h=r-(S)/(2pi r) D h=(2S)/(pi r)-r

To solve for h in the given formula, we need to isolate h on one side of the equation.<br /><br />Given formula: $S=2(\pi r^{2}+\pi rh)$<br /><br />Step 1: Divide both sides of the equation by 2 to get rid of the 2 on the right side.<br />$S/2 = \pi r^{2}+\pi rh$<br /><br />Step 2: Subtract $\pi r^{2}$ from both sides to isolate the term with h.<br />$S/2 - \pi r^{2} = \pi rh$<br /><br />Step 3: Divide both sides by $\pi r$ to solve for h.<br />$h = \frac{S/2 - \pi r^{2}}{\pi r}$<br /><br />Therefore, the correct answer is:<br />C. $h=r-\frac {S}{2\pi r}$