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(6) The temperature of a city was measured at 8 a.m. each day for three days. On Day 1, the temperature was t^circ C On Day 2, it was twice the temperature on Day 1. On Day 3, it decreased by 3^circ C What was the temperature on Day 1 if it was 9^circ C on Day 3?

Pergunta

(6) The temperature of a city was measured at 8 a.m. each day for three days. On Day 1,
the temperature was t^circ C
On Day 2, it was twice the temperature on Day 1. On Day 3, it decreased by 3^circ C
What was the temperature on Day 1 if it was
9^circ C on Day 3?

(6) The temperature of a city was measured at 8 a.m. each day for three days. On Day 1, the temperature was t^circ C On Day 2, it was twice the temperature on Day 1. On Day 3, it decreased by 3^circ C What was the temperature on Day 1 if it was 9^circ C on Day 3?

Solução

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Yara MariaEspecialista · Tutor por 3 anos

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Here's how to solve the problem:<br /><br />* **Day 2:** The temperature on Day 2 was twice the temperature on Day 1, so it was 2 * t degrees Celsius.<br />* **Day 3:** The temperature on Day 3 was 3 degrees Celsius less than Day 2, so it was (2 * t) - 3 degrees Celsius.<br />* **Given:** We know the temperature on Day 3 was 9 degrees Celsius.<br />* **Equation:** We can set up an equation: (2 * t) - 3 = 9<br />* **Solve for t:**<br /> * Add 3 to both sides: 2 * t = 12<br /> * Divide both sides by 2: t = 6<br /><br />**Therefore, the temperature on Day 1 was 6 degrees Celsius.** <br />
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