solution of HCL How many mL of 119MHC ad to make 250 mL of 200MHC " 1.25mL 25.5mL 124mL 420mL

To solve this problem, we need to use the concept of dilution formula for calculating the amount of solute in a solution.<br /><br />Given information:<br />- Initial concentration of HCl solution: 119M<br />- Final concentration of HCl solution: 200M<br />- Final volume of the solution: 250 mL<br /><br />We need to find the volume of the initial 119M HCl solution that needs to be added to make 250 mL of 200M HCl solution.<br /><br />Let's denote the volume of the initial 119M HCl solution as V1.<br /><br />The amount of HCl in the final 200M solution is equal to the amount of HCl in the initial 119M solution.<br /><br />Amount of HCl in the final 200M solution = 200M × 250 mL = 50,000 mmol<br /><br />Amount of HCl in the initial 119M solution = 119M × V1<br /><br />Equating the two amounts, we get:<br /><br />119M × V1 = 50,000 mmol<br /><br />Solving for V1, we get:<br /><br />V1 = 50,000 mmol / 119M = 420 mL<br /><br />Therefore, the correct answer is 420 mL.