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30. Solve 3(x-4)^2-12=0 a=-2or-6 =2 or 6 n=10 m=89

Pergunta

30. Solve 3(x-4)^2-12=0
a=-2or-6
=2 or 6
n=10
m=89

30. Solve 3(x-4)^2-12=0 a=-2or-6 =2 or 6 n=10 m=89

Solução

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RenanProfissional · Tutor por 6 anos

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To solve the equation $3(x-4)^{2}-12=0$, we can follow these steps:<br /><br />1. Add 12 to both sides of the equation:<br />$3(x-4)^{2} = 12$<br /><br />2. Divide both sides by 3:<br />$(x-4)^{2} = 4$<br /><br />3. Take the square root of both sides:<br />$x-4 = \pm 2$<br /><br />4. Add 4 to both sides:<br />$x = 4 \pm 2$<br /><br />So, the solutions to the equation are $x = 6$ and $x = 2$.<br /><br />Therefore, the correct answer is $x = 6$ or $x = 2$.
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