Given: f(x)=2x+5 and g(x)=x^2 and h(x)=-2x square h(g(f(x)))=-8vx^2+-40vx+-50v 50 -50 25

To find the value of $h(g(f(x)))$, we need to substitute the given functions into each other step by step.<br /><br />First, let's find $f(x)$:<br />$f(x) = 2x + 5$<br /><br />Next, substitute $f(x)$ into $g(x)$:<br />$g(f(x)) = g(2x + 5) = (2x + 5)^2$<br /><br />Now, substitute $g(f(x))$ into $h(x)$:<br />$h(g(f(x))) = h((2x + 5)^2) = -2(2x + 5)^2$<br /><br />Expanding and simplifying the expression:<br />$h(g(f(x))) = -2(4x^2 + 20x + 25) = -8x^2 - 40x - 50$<br /><br />Therefore, the correct answer is $-50$.