Consider 8x^2-48x=-104 Write the equation so that a=1:x^2+-6 surd x=- xLongrightarrow -13 COMPLETE Complete the square: x^2-6x+9 surd =-13+9 Factor the trinomial and simplify: (x+square )^2=square

To solve the equation $8x^{2}-48x=-104$, we first rewrite it in the form $x^{2}-6x=-13$ by dividing both sides by 8.<br /><br />Next, we complete the square by adding $\left(\frac{-6}{2}\right)^{2}=9$ to both sides of the equation:<br /><br />$x^{2}-6x+9=-13+9$<br /><br />This simplifies to:<br /><br />$(x-3)^{2}=-4$<br /><br />Taking the square root of both sides, we get:<br /><br />$x-3=\pm\sqrt{-4}$<br /><br />Since $\sqrt{-4}=2i$, we have:<br /><br />$x-3=\pm2i$<br /><br />Finally, solving for $x$, we get:<br /><br />$x=3\pm2i$<br /><br />So the solutions to the equation are $x=3+2i$ and $x=3-2i$.