Add (3-5i)+(-2+8i) Sum of real parts: square Sum of imaginary parts: square COMPLETE The sum of (3-5i)+(-2+8i) is times 3+i 3-i 1+3i -1-3i

To add the complex numbers \((3-5i) + (-2+8i)\), we need to add the real parts and the imaginary parts separately.<br /><br />First, let's add the real parts:<br />\[ 3 + (-2) = 3 - 2 = 1 \]<br /><br />Next, let's add the imaginary parts:<br />\[ -5i + 8i = 3i \]<br /><br />So, the sum of \((3-5i) + (-2+8i)\) is:<br />\[ 1 + 3i \]<br /><br />Therefore, the correct answer is:<br />\[ 1 + 3i \]