The length of a rectangle is 4 in longer than its width. If the perimeter of the rectangle is 32 in, find its area. square in^2

## Step 1<br />Let's denote the width of the rectangle as \(x\). According to the problem, the length of the rectangle is \(x + 4\).<br /><br />## Step 2<br />The perimeter of a rectangle is calculated by the formula:<br />### \(P = 2 \times (length + width)\)<br />Substituting the given values into the formula, we get:<br />### \(32 = 2 \times (x + (x + 4))\)<br /><br />## Step 3<br />Solving the equation for \(x\), we find that \(x = 12\). Therefore, the width of the rectangle is 12 inches.<br /><br />## Step 4<br />The length of the rectangle is \(x + 4 = 12 + 4 = 16\) inches.<br /><br />## Step 5<br />The area of a rectangle is calculated by the formula:<br />### \(A = length \times width\)<br />Substituting the values of the length and width into the formula, we get:<br />### \(A = 12 \times 16 = 192\)