Solve x^2-8x-9=0 Rewrite the equation so that it is of the form x^2+bx=c x^2+-8 surd x=9 COMPUTE Add -1 XLongrightarrow 16 each side x^2-8x=9 complete the square. Now that you have x^2-8x+16=9+16 apply the square root property to the equation. (x-4)^2=25 (x+16)^2=25 (x-4)^2=9 (x+16)^2=9

To solve the equation $x^{2}-8x-9=0$, we can rewrite it in the form $x^{2}+bx=c$ by adding 9 to both sides of the equation:<br /><br />$x^{2}-8x=9$<br /><br />Next, we complete the square by adding $\left(\frac{-8}{2}\right)^2 = 16$ to both sides of the equation:<br /><br />$x^{2}-8x+16=9+16$<br /><br />Simplifying, we get:<br /><br />$(x-4)^{2}=25$<br /><br />Now, we can apply the square root property to solve for $x$:<br /><br />$x-4=\pm\sqrt{25}$<br /><br />$x-4=\pm5$<br /><br />Solving for $x$, we get:<br /><br />$x=4\pm5$<br /><br />Therefore, the solutions to the equation $x^{2}-8x-9=0$ are $x=4+5=9$ and $x=4-5=-1$.