prmation function f(x,y)=(2x-3,2y+5) is (1,-2),(3,-1),(4,-4) What is the range of the

To find the range of the function $f(x,y)=(2x-3,2y+5)$, we need to determine the possible values of the output coordinates.<br /><br />Given the points $(1,-2)$, $(3,-1)$, and $(4,-4)$, we can substitute these values into the function to find the corresponding output coordinates.<br /><br />For the point $(1,-2)$:<br />$f(1,-2) = (2(1)-3, 2(-2)+5) = (-1,1)$<br /><br />For the point $(3,-1)$:<br />$f(3,-1) = (2(3)-3, 2(-1)+5) = (3,3)$<br /><br />For the point $(4,-4)$:<br />$f(4,-4) = (2(4)-3, 2(-4)+5) = (5,-3)$<br /><br />Therefore, the range of the function $f(x,y)=(2x-3,2y+5)$ is $\{(-1,1), (3,3), (5,-3)\}$.