Pergunta

Write an equation in point-slope form of the line that passes through the point (-3,0) and has a slope of -(1)/(3) The equation is y-square =square (x-square )
Solução

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RenataProfissional · Tutor por 6 anos
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To write the equation of a line inlope form, we use the formula:<br /><br />\[ y - y_1 = m(x - x_1) \]<br /><br />where \((x_1, y_1)\) is a point on the line and \(m\) is the slope of the line.<br /><br />Given:<br />- Point: \((-3, 0)\)<br />- Slope: \(m = -\frac{1}{3}\)<br /><br />Substitute these values into the point-slope form equation:<br /><br />\[ y - 0 = -\frac{1}{3}(x - (-3)) \]<br /><br />Simplify the equation:<br /><br />\[ y = -\frac{1}{3}(x + 3) \]<br /><br />So, the equation in point-slope form is:<br /><br />\[ y - 0 = -\frac{1}{3}(x + 3) \]<br /><br />Therefore, the equation is:<br /><br />\[ y - \square = \square (x - \square) \]<br /><br />where:<br />- The first blank (\(\square\)) is \(0\)<br />- The second blank (\(\square\)) is \(-\frac{1}{3}\)<br />- The third blank (\(\square\)) is \(3\)<br /><br />Thus, the final equation is:<br /><br />\[ y - 0 = -\frac{1}{3}(x + 3) \]
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