Use the quadratic formula to solve for x. 2x^2+3x-7=0 (If there is more than one solution, separate them with comm x=

To solve the quadratic equation $2x^{2}+3x-7=0$ using the quadratic formula, we can use the formula:<br /><br />$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$<br /><br />where $a$, $b$, and $c$ are the coefficients of the quadratic equation.<br /><br />In this case, $a = 2$, $b = 3$, and $c = -7$.<br /><br />Substituting these values into the formula, we get:<br /><br />$x = \frac{-3 \pm \sqrt{3^2 - 4(2)(-7)}}{2(2)}$<br /><br />Simplifying further:<br /><br />$x = \frac{-3 \pm \sqrt{9 + 56}}{4}$<br /><br />$x = \frac{-3 \pm \sqrt{65}}{4}$<br /><br />Therefore, the solutions to the quadratic equation $2x^{2}+3x-7=0$ are:<br /><br />$x = \frac{-3 + \sqrt{65}}{4}$ and $x = \frac{-3 - \sqrt{65}}{4}$