2) Resolva: a) (2)/(3)+(3)/(4)= b) (3)/(5)+(1)/(2)+(3)/(10)= c) (7)/(8)-(5)/(8)= d) 3-(5)/(6)= e) (1)/(4)+(1)/(3)-(5)/(6)= f) (1)/(3)-(4)/(3)=

a) $\frac{2}{3} + \frac{3}{4} = \frac{8}{12} + \frac{9}{12} = \frac{17}{12} = 1\frac{5}{12}$<br /><br />b) $\frac{3}{5} + \frac{1}{2} + \frac{3}{10} = \frac{6}{10} + \frac{5}{10} + \frac{3}{10} = \frac{14}{10} = 1\frac{4}{10} = 1\frac{2}{5}$<br /><br />c) $\frac{7}{8} - \frac{5}{8} = \frac{2}{8} = \frac{1}{4}$<br /><br />d) $3 - \frac{5}{6} = \frac{18}{6} - \frac{5}{6} = \frac{13}{6} = 2\frac{1}{6}$<br /><br />e) $\frac{1}{4} + \frac{1}{3} - \frac{5}{6} = \frac{3}{12} + \frac{4}{12} - \frac{10}{12} = \frac{7}{12} - \frac{10}{12} = -\frac{3}{12} = -\frac{1}{4}$<br /><br />f) $\frac{1}{3} - \frac{4}{3} = \frac{1}{3} - \frac{4}{3} = -\frac{3}{3} = -1$