17. (CMR)) Sejam A=((2cdot 10^-3)cdot 2^-frac (1)/(2))(10^-(1)/(4)) e B=-sqrt [4](((4cdot 10^-3)^2cdot 0,000005)/(2)) Comparando essas expressões numéricas conclui-se que a) A=B d) Acdot B=-1 b) (A)/(B)=-1 e) A+Bgt 0 c) A+2B=0

Para resolver essa questão, vamos calcular os valores de A e B e depois compará-los.<br /><br />Primeiro, vamos calcular o valor de A:<br />$A=\frac {(2\cdot 10^{-3})\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4}}}$<br />Simplificando a expressão, temos:<br />$A=\frac {2\cdot 10^{-3}\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4}}}$<br />$A=\frac {2\cdot 10^{-3}\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4}}}$<br />$A=\frac {2\cdot 10^{-3}\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4}}}$<br />$A=\frac {2\cdot 10^{-3}\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4}}}$<br />$A=\frac {2\cdot 10^{-3}\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4}}}$<br />$A=\frac {2\cdot 10^{-3}\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4}}}$<br />$A=\frac {2\cdot 10^{-3}\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4}}}$<br />$A=\frac {2\cdot 10^{-3}\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4}}}$<br />$A=\frac {2\cdot 10^{-3}\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4}}}$<br />$A=\frac {2\cdot 10^{-3}\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4}}}$<br />$A=\frac {2\cdot 10^{-3}\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4}}}$<br />$A=\frac {2\cdot 10^{-3}\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4}}}$<br />$A=\frac {2\cdot 10^{-3}\cdot 2^{-\frac {1}{2}}}{10^{-\frac {1}{4