Pergunta

18. (32x^3y^2z^5)/(-8xyz^2)
Solução

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To simplify the expression $\frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}}$, we can follow these steps:<br /><br />1. Factor out common terms in the numerator and denominator.<br />2. Cancel out the common terms.<br />3. Simplify the resulting expression.<br /><br />Step 1: Factor out common terms in the numerator and denominator.<br />$\frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}}$<br /><br />Step 2: Cancel out the common terms.<br />$\frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8xyz^{2}} = \frac {32x^{3}y^{2}z^{5}}{-8
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