What are the roots of the equation x^2-18x+82

To find the roots of the quadratic equation $x^2 - 18x + 82 = 0$, we can use the quadratic formula:<br /><br />$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$<br /><br />where $a$, $b$, and $c$ are the coefficients of the quadratic equation.<br /><br />In this case, $a = 1$, $b = -18$, and $c = 82$.<br /><br />Substituting these values into the quadratic formula, we get:<br /><br />$x = \frac{-(-18) \pm \sqrt{(-18)^2 - 4(1)(82)}}{2(1)}$<br /><br />$x = \frac{18 \pm \sqrt{324 - 328}}{2}$<br /><br />$x = \frac{18 \pm \sqrt{-4}}{2}$<br /><br />$x = \frac{18 \pm 2i}{2}$<br /><br />$x = 9 \pm i$<br /><br />Therefore, the roots of the equation $x^2 - 18x + 82 = 0$ are $x = 9 + i$ and $x = 9 - i$.