10) Calcule o valor de: a) 4!= b) 0!= c) 11= d) (9!)/(6!) e) (71)/(41)= f) (7!4!)/(5!3!)=

a) $4! = 4 \times 3 \times 2 \times 1 = 24$<br />b) $0! = 1$ (por definição, o fatorial de zero é igual a 1)<br />c) $11! = 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 39.916.800$<br />d) $\frac{9!}{6!} = \frac{9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} = 9 \times 8 \times 7 = 504$<br />e) $\frac{71}{41} = 1.731$ (aproximadamente)<br />f) $\frac{7! \times 4!}{5! \times 3!} = \frac{7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \times 4 \times 3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1 \times 3 \times 2 \times 1} = 7 \times 4 = 28$