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What is the equation of the line that passes through the point (-1,5) and has a slope of -3? Answer Attemptiout of 2
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FrancielleMestre · Tutor por 5 anos
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To find the equation of the line that passes through the point $(-1,5)$ and has a slope of $-3$, we can use the point-slope form of a linear equation.<br /><br />The point-slope form of a linear equation is given by:<br />\[ y - y_1 = m(x - x_1) \]<br />where $(x_1, y_1)$ is a point on the line and $m$ is the slope of the line.<br /><br />In this case, we are given the point $(-1,5)$ and the slope $-3$. Plugging these values into the point-slope form, we get:<br />\[ y - 5 = -3(x - (-1)) \]<br /><br />Simplifying the equation, we have:<br />\[ y - 5 = -3(x + 1) \]<br />\[ y - 5 = -3x - 3 \]<br />\[ y = -3x + 2 \]<br /><br />Therefore, the equation of the line that passes through the point $(-1,5)$ and has a slope of $-3$ is:<br />\[ y = -3x + 2 \]
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