Pergunta

29. Multiply (2x+7)(3x+1) 6x^2+7 6x^2+21x+7 6x+7 6x^2+23x+7
Solução

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ArturMestre · Tutor por 5 anos
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To multiply \((2x+7)(3x+1)\), we use the distributive property (also known as the FOIL method for binomials):<br /><br />\[<br />(2x+7)(3x+1) = 2x \cdot 3x + 2x \cdot 1 + 7 \cdot 3x + 7 \cdot 1<br />\]<br /><br />Now, calculate each term:<br /><br />\[<br />2x \cdot 3x = 6x^2<br />\]<br />\[<br />2x \cdot 1 = 2x<br />\]<br />\[<br />7 \cdot 3x = 21x<br />\]<br />\[<br />7 \cdot 1 = 7<br />\]<br /><br />Next, combine the like terms:<br /><br />\[<br />6x^2 + 2x + 21x + 7 = 6x^2 + 23x + 7<br />\]<br /><br />So, the correct answer is:<br /><br />\[<br />6x^2 + 23x + 7<br />\]<br /><br />Therefore, the correct option is:<br /><br />$6x^{2}+23x+7$
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