Pergunta
x^2+6x+5 Answer Attemptiout of 2 square
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MateoVeterano · Tutor por 12 anos
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To solve the quadratic equation $x^{2}+6x+5$, we can use the quadratic formula:<br /><br />$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$<br /><br />where $a$, $b$, and $c$ are the coefficients of the quadratic equation.<br /><br />In this case, $a = 1$, $b = 6$, and $c = 5$. Plugging these values into the quadratic formula, we get:<br /><br />$x = \frac{-6 \pm \sqrt{6^2 - 4(1)(5)}}{2(1)}$<br /><br />Simplifying further, we have:<br /><br />$x = \frac{-6 \pm \sqrt{ }$<br /><br />$x = \frac{-6 \pm \sqrt{16}}{2}$<br /><br />$x = \frac{-6 \pm 4}{2}$<br /><br />This gives us two possible solutions:<br /><br />$x_1 = \frac{-6 + 4}{2} = -1$<br /><br />$x_2 = \frac{-6 - 4}{2} = -5$<br /><br />Therefore, the solutions to the quadratic equation $x^{2}+6x+5$ are $x = -1$ and $x = -5$.
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