In a certain country the true probability of a baby being a boy is 0.538. Among the next nine randomly selected births in the country.what is the probability that at least one of them is a girl? The probability is square (Round to three decimal places as needed.)

To solve this problem, we can use the concept of complementary probability.<br /><br />Given information:<br />- The true probability of a baby being a boy is 0.538.<br />- We need to find the probability that at least one of the next nine randomly selected births is a girl.<br /><br />Step 1: Calculate the probability of a baby being a girl.<br />Probability of a baby being a girl = 1 - Probability of a baby being a boy<br />Probability of a baby being a girl = 1 - 0.538 = 0.462<br /><br />Step 2: Calculate the probability of all nine babies being boys.<br />Probability of all nine babies being boys = (Probability of a baby being a boy)^9<br />Probability of all nine babies being boys = (0.538)^9 = 0.002<br /><br />Step 3: Calculate the probability of at least one baby being a girl.<br />Probability of at least one baby being a girl = 1 - Probability of all nine babies being boys<br />Probability of at least one baby being a girl = 1 - 0.002 = 0.998<br /><br />Therefore, the probability that at least one of the next nine randomly selected births is a girl is 0.998 (rounded to three decimal places).