Question 2-5 Text Entry -1 point for correct answer Solve the equation 25^(x+1)=125 Enter your afiswer as a decimal or as a simplified fraction. Enter a number only. x=square

To solve the equation $25^{(x+1)}=125$, we can rewrite both sides of the equation with the same base.<br /><br />$25^{(x+1)}=125$<br /><br />$(5^2)^{(x+1)}=5^3$<br /><br />$5^{2(x+1)}=5^3$<br /><br />Since the bases are the same, we can equate the exponents:<br /><br />$2(x+1)=3$<br /><br />$2x+2=3$<br /><br />$2x=1$<br /><br />$x=\frac{1}{2}$<br /><br />Therefore, the solution to the equation is $x=\frac{1}{2}$.