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If a 9-Watt light bulb is on for 3 seconds, how much energy did it put out? A 1/3 of a Joule 3 Joules 27 Joules 3 degrees Kelvin __ 27 degrees Kelvin

Pergunta

If a 9-Watt light bulb is on for 3 seconds, how much energy did it put out?
A 1/3 of a Joule
3 Joules
27 Joules
3 degrees Kelvin
__ 27 degrees Kelvin

If a 9-Watt light bulb is on for 3 seconds, how much energy did it put out? A 1/3 of a Joule 3 Joules 27 Joules 3 degrees Kelvin __ 27 degrees Kelvin

Solução

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The light bulb put out 27 Joules of energy.

Explicação

## Step 1<br />The power of a device is the rate at which it consumes energy. In this case, the power of the light bulb is given as 9 Watts. This means that the bulb consumes 9 Joules of energy every second.<br /><br />## Step 2<br />The light bulb is on for 3 seconds. Therefore, the total energy consumed by the bulb is the product of the power and the time.<br /><br />### **Energy = Power * Time**<br /><br />## Step 3<br />Substitute the given values into the formula.<br /><br />### **Energy = 9 Watts * 3 seconds**
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