Primeira página
/
Matemática
/
Use technology or az-score table to answer the question. The number of huckleberries picked during a huckleberry contest are normally distributed with a mean of 300 and a standard deviation of 53. Jill picked 276 huckleberries in the contest. What percent of huckleberry pickers picked less than Jill? Round your answer to the nearest whole number. 24% 33% 45% 52%

Pergunta

Use technology or az-score table to answer the question.
The number of huckleberries picked during a huckleberry contest are normally distributed with a mean of 300 and a standard
deviation of 53. Jill picked 276 huckleberries in the contest.
What percent of huckleberry pickers picked less than Jill?
Round your answer to the nearest whole number.
24% 
33% 
45% 
52%

Use technology or az-score table to answer the question. The number of huckleberries picked during a huckleberry contest are normally distributed with a mean of 300 and a standard deviation of 53. Jill picked 276 huckleberries in the contest. What percent of huckleberry pickers picked less than Jill? Round your answer to the nearest whole number. 24% 33% 45% 52%

Solução

expert verifiedVerification of experts
4.5251 Voting
avatar
Karla MariaProfissional · Tutor por 6 anos

Responder

To find the percentage of huckleberry pickers who picked less than Jill, we need to calculate the z-score for Jill's score and then use the z-score table to find the corresponding percentage.<br /><br />The z-score is calculated using the formula:<br /><br />z = (X - μ) / σ<br /><br />where:<br />X = Jill's score (276)<br />μ = mean (300)<br />σ = standard deviation (53)<br /><br />Plugging in the values, we get:<br /><br />z = (276 - 300) / 53<br />z = -24 / 53<br />z ≈ -0.45<br /><br />Now, we can use the z-score table to find the corresponding percentage. The z-score of -0.45 corresponds to a percentage of approximately 33%.<br /><br />Therefore, the answer is $33\%$.
Clique para avaliar: