Pergunta

6 Multiple Choice 1 point An experiment in a general chemistry laboratory calls for a 2.00 M solution of HCL How many mL of 11.9 MHCI I would be required to make 250 mL of 200M HCI? 1.25 mL 25.5 mL 12.6 mL 42.0 mL
Solução

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JosiElite · Tutor por 8 anos
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### Step 1<br />The problem involves the concept of molarity and dilution in chemistry. The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. The formula for dilution is given by:<br />### \(M1V1 = M2V2\)<br />where \(M1\) is the initial molarity, \(V1\) is the initial volume, \(M2\) is the final molarity, and \(V2\) is the final volume.<br /><br />## Step 2<br />In this problem, we are given \(M1 = 11.9M\), \(M2 = 2.00M\), and \(V2 = 250mL\). We are asked to find \(V1\), the initial volume.<br /><br />## Step 3<br />We can rearrange the dilution formula to solve for \(V1\):<br />### \(V1 = \frac{M2V2}{M1}\)<br /><br />## Step 4<br />Substitute the given values into the formula:<br />### \(V1 = \frac{2.00M * 250mL}{11.9M}\)<br /><br />## Step 5<br />Calculate the value of \(V1\).<br /><br /># Answer: <br />The initial volume \(V1\) is approximately 42.0 mL.
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