Consider 8x^2-48x=-104 Write the equation so that a=1:x^2+-6 surd x=- XLongrightarrow -13 COMPLETE Complete the square: x^2-6x+9 surd =-13+9 Factor the trinomial and simplify: (x+-3 surd )^2=-4 COMPLETE Use the square root property of equality to solve (x-3)^2=-4 The solutions are DONE -1 or 1015 3pm 2i 3pm 4i

To solve the equation $8x^{2}-48x=-104$, we can follow these steps:<br /><br />1. Rewrite the equation in the form $ax^{2}+bx+c=0$:<br />$8x^{2}-48x+104=0$<br /><br />2. Divide the entire equation by 8 to simplify:<br />$x^{2}-6x+13=0$<br /><br />3. Complete the square:<br />$x^{2}-6x+9=13-9$<br />$(x-3)^{2}=4$<br /><br />4. Use the square root property of equality to solve:<br />$x-3=\pm 2i$<br />$x=3\pm 2i$<br /><br />Therefore, the solutions to the equation $8x^{2}-48x=-104$ are $x=3\pm 2i$.