(x-12)(x-4) Factor x^2-16x+48 (x+12)(x-4) (x+6)(x-8) (x-16)(x-3)

To factor the expression $(x-12)(x-4)$, we need to expand it and then factor the resulting quadratic expression.<br /><br />Expanding $(x-12)(x-4)$:<br />$(x-12)(x-4) = x^2 - 4x - 12x + 48 = x^2 - 16x + 48$<br /><br />Now, we need to factor the quadratic expression $x^2 - 16x + 48$.<br /><br />The correct factorization is:<br />$(x-12)(x-4)$<br /><br />Therefore, the correct answer is:<br />$(x-12)(x-4)$